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1e4 e5 2 f4 exf4 3 Nf3
(Click on Column Number to see varation
in Play)
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Cunningham Variation
d5............................................................................................................................Be7
4
exd5
Bc4...................Nc3
Nf6........................................................................................
Bd6
Nf6 (m)
Nf6 (p)
5
Nc3....................Bb5+..........................c4
Nc3
e5 (n)
e5 (q)
Nxd5 (a)
c6
c6
Ne7
Ng4
Ng4
6
Nxd5
dxc6
d4 (h)
d4
Nc3
d4
Qxd5
bxc6 (f)
Bb4+ (i)
0-0
d6
Ne3
7
d4
Bc4
Nc3
Bd3
d4
Bxe3
Be7 (b)
Nd5
cxd5
Nd7
dxe5
fxe3
8
c4 (c)
Nc3 (g)
Bxf4
0-0
dxe5
Bc4
Q34+
Be7
0-0
h6 (k)
Qxd1+
d6
9
Kf2 (d)
0-0
Be2
Ne4
Nxd1
0-0
Bf5
0-0
dxc4
Nxd5
Be6
0-0
10
Be2 (e)
d4
Bxc4
c4
Bxe6
Qd3
Nc6=
Nb6=
N d5 (j)
Ne3 (l)
fxe6 (o)
Nc6 (r)
(a) After 5.....Bd6 6 Bc4 0-0 7 0-0 Nbd7 8 d4 Nb6 9 Bb3 h6 10 Ne5 g5, White makes a promising exchange sacrifice with 11 g3 Bh3 12 Gxf4.
(b) Both (A) 7.....bD6 8 C4 Qe4+ 9 Kf2 and (B) 7.....Bg4 8 Bxf4 are better for White.
(c) 8 Bd3 g5 and not Rubinstein's 9 Qe2?! but 9 c4 (Euwe) produces an interesting game.
(d) 9 Be2 Bf5 10 0-0 Nc6 =, Spielmann-Milner-Barry, Margate 1938.
(f) 6.....Nxc6, played in Hartston_Spassky, Hasting 1966 is all right, but after 7 d4 Bd6 8 0-0 0-0 9 Nbd2 Bg4 10 Nc4 Bc7 11 Bxc6 White has a slight plus.
(g) The text is a improvement over 8 0-0 Bd6 9 Nc3 Be6 since 8 Nc3 Bd6 9 Qe2! is strong. The column is Muchnik-Lilienthal, USSR 1967
(h) 6 dxc6 Nxc6 7 d4 give Black to much play.
(i) 6.....cxd5 7 c5 Nc6 8 Bxf4 Be7 9 Nc3 0-0 =
(j) With no difficulties and good pawn structure Black has at least equality.
(k) 8.....Nf6 is an improvement which gives chances for equality. If Black wants to play 4.....Bd6 he must find something better than the continuation in the column.
(l)
11 Bxe3 fxe3 12 c5 Be7 13 Bc2 Re8 14 Qd3 e2 15 Nd6! Nf8 16 Nxf7 exf1=Q+
17 Rxf1
Bf5 18 Qxf5 Qd7 19 Qf4 Bf6 20 N3e5
Qe7 21 Bb3 Bxe5 22 Nxe5+ Kh7 23 Qe4+ Resignes, Spassky-Bronstein, USSR
1960; a truly brilliant game.
(m) 4.....Bh4+ 5 Kf1 (better than the speculative 5 g3) d5 6 Bxd5 Nf6 and now Glazkov's 7 Bb3 gives White chances for an edge.
(n) (A) 5 nc3 Nxe4 6 Ne5 Ng5 =+. (B) 5 Qe2 and (C) 5 de produce only equality.
(o) 11 h3 Nh6 12 Bxf4 Nf5 = (Korchnoi).
(p) 4 .....Bh4+ is also logical. After 5 Ke2 d5 6 Nxd5 Nf6 7 Nxf6+ Qxf6 8 d4 the question is whether White's Center is worth more than his exposed King.
(q) 5 d4 d5 6 Bd3 (or 6 exd5) gives WHite little chance for an edge.
(r)
11 exd6 Bxd6 12 Ne4 Be7 =.